4-2(y-3)=16

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Solution for 4-2(y-3)=16 equation: 



4-2(y-3)=16

We move all terms to the left:

4-2(y-3)-(16)=0

We add all the numbers together, and all the variables

-2(y-3)-12=0

We multiply parentheses

-2y+6-12=0

We add all the numbers together, and all the variables

-2y-6=0

We move all terms containing y to the left, all other terms to the right

-2y=6

y=6/-2

y=-3

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