4-2(z-4)/3=1/2(2z+5))

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Solution for 4-2(z-4)/3=1/2(2z+5)) equation: 



4-2(z-4)/3=1/2(2z+5))

We move all terms to the left:

4-2(z-4)/3-(1/2(2z+5)))=0



Domain of the equation: 2(2z+5)))+4!=0

z∈R



We calculate fractions


(-2(z-4)*2(2z+5)))+4)/(6z2+()/(6z2=0

We can not solve this equation

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