4-2(z-5)=z-19

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Solution for 4-2(z-5)=z-19 equation: 



4-2(z-5)=z-19

We move all terms to the left:

4-2(z-5)-(z-19)=0

We multiply parentheses

-2z-(z-19)+10+4=0

We get rid of parentheses

-2z-z+19+10+4=0

We add all the numbers together, and all the variables

-3z+33=0

We move all terms containing z to the left, all other terms to the right

-3z=-33

z=-33/-3

z=+11

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