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4-2x+3=-3(x-4)
We move all terms to the left:
4-2x+3-(-3(x-4))=0
We add all the numbers together, and all the variables
-2x-(-3(x-4))+7=0
We calculate terms in parentheses: -(-3(x-4)), so:We get rid of parentheses
-3(x-4)
We multiply parentheses
-3x+12
Back to the equation:
-(-3x+12)
-2x+3x-12+7=0
We add all the numbers together, and all the variables
x-5=0
We move all terms containing x to the left, all other terms to the right
x=5
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