4-2x=-3(2/3x)-3

Solution for 4-2x=-3(2/3x)-3 equation:

4-2x=-3(2/3x)-3

We move all terms to the left:

4-2x-(-3(2/3x)-3)=0


Domain of the equation: 3x)-3)!=0

x!=0/1

x!=0

x∈R


We add all the numbers together, and all the variables

-2x-(-3(+2/3x)-3)+4=0

We multiply all the terms by the denominator


-2x*3x)-3)-(-3(+4*3x)-3)+2=0

Wy multiply elements

-6x^2+12x=0

a = -6; b = 12; c = 0;
Δ = b2-4ac
Δ = 122-4·(-6)·0
Δ = 144
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{144}=12$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-12}{2*-6}=\frac{-24}{-12}
=+2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+12}{2*-6}=\frac{0}{-12}
=0
$