4-3(2y-1)=7+4(5-y)

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Solution for 4-3(2y-1)=7+4(5-y) equation: 



4-3(2y-1)=7+4(5-y)

We move all terms to the left:

4-3(2y-1)-(7+4(5-y))=0

We add all the numbers together, and all the variables

-3(2y-1)-(7+4(-1y+5))+4=0

We multiply parentheses

-6y-(7+4(-1y+5))+3+4=0



We calculate terms in parentheses: -(7+4(-1y+5)), so:

7+4(-1y+5)

determiningTheFunctionDomain
4(-1y+5)+7

We multiply parentheses

-4y+20+7

We add all the numbers together, and all the variables

-4y+27

Back to the equation:

-(-4y+27)



We add all the numbers together, and all the variables

-6y-(-4y+27)+7=0

We get rid of parentheses

-6y+4y-27+7=0

We add all the numbers together, and all the variables

-2y-20=0

We move all terms containing y to the left, all other terms to the right

-2y=20

y=20/-2

y=-10

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