4-3(7+2x)=2(5x-4)+7

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Solution for 4-3(7+2x)=2(5x-4)+7 equation: 



4-3(7+2x)=2(5x-4)+7

We move all terms to the left:

4-3(7+2x)-(2(5x-4)+7)=0

We add all the numbers together, and all the variables

-3(2x+7)-(2(5x-4)+7)+4=0

We multiply parentheses

-6x-(2(5x-4)+7)-21+4=0



We calculate terms in parentheses: -(2(5x-4)+7), so:

2(5x-4)+7

We multiply parentheses

10x-8+7

We add all the numbers together, and all the variables

10x-1

Back to the equation:

-(10x-1)



We add all the numbers together, and all the variables

-6x-(10x-1)-17=0

We get rid of parentheses

-6x-10x+1-17=0

We add all the numbers together, and all the variables

-16x-16=0

We move all terms containing x to the left, all other terms to the right

-16x=16

x=16/-16

x=-1

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