4-3(n-5)=5(2n-4)

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Solution for 4-3(n-5)=5(2n-4) equation: 



4-3(n-5)=5(2n-4)

We move all terms to the left:

4-3(n-5)-(5(2n-4))=0

We multiply parentheses

-3n-(5(2n-4))+15+4=0



We calculate terms in parentheses: -(5(2n-4)), so:

5(2n-4)

We multiply parentheses

10n-20

Back to the equation:

-(10n-20)



We add all the numbers together, and all the variables

-3n-(10n-20)+19=0

We get rid of parentheses

-3n-10n+20+19=0

We add all the numbers together, and all the variables

-13n+39=0

We move all terms containing n to the left, all other terms to the right

-13n=-39

n=-39/-13

n=+3

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