4-3(q+5)=-2(7q-6)+32

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Solution for 4-3(q+5)=-2(7q-6)+32 equation: 



4-3(q+5)=-2(7q-6)+32

We move all terms to the left:

4-3(q+5)-(-2(7q-6)+32)=0

We multiply parentheses

-3q-(-2(7q-6)+32)-15+4=0



We calculate terms in parentheses: -(-2(7q-6)+32), so:

-2(7q-6)+32

We multiply parentheses

-14q+12+32

We add all the numbers together, and all the variables

-14q+44

Back to the equation:

-(-14q+44)



We add all the numbers together, and all the variables

-3q-(-14q+44)-11=0

We get rid of parentheses

-3q+14q-44-11=0

We add all the numbers together, and all the variables

11q-55=0

We move all terms containing q to the left, all other terms to the right

11q=55

q=55/11

q=5

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