4-3(x+2)=-7x-12+(2x+5)

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Solution for 4-3(x+2)=-7x-12+(2x+5) equation: 



4-3(x+2)=-7x-12+(2x+5)

We move all terms to the left:

4-3(x+2)-(-7x-12+(2x+5))=0

We multiply parentheses

-3x-(-7x-12+(2x+5))-6+4=0



We calculate terms in parentheses: -(-7x-12+(2x+5)), so:

-7x-12+(2x+5)

determiningTheFunctionDomain
-7x+(2x+5)-12

We get rid of parentheses

-7x+2x+5-12

We add all the numbers together, and all the variables

-5x-7

Back to the equation:

-(-5x-7)



We add all the numbers together, and all the variables

-3x-(-5x-7)-2=0

We get rid of parentheses

-3x+5x+7-2=0

We add all the numbers together, and all the variables

2x+5=0

We move all terms containing x to the left, all other terms to the right

2x=-5

x=-5/2

x=-2+1/2

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