4-3(x+2)=6(x-2)-7

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Solution for 4-3(x+2)=6(x-2)-7 equation: 



4-3(x+2)=6(x-2)-7

We move all terms to the left:

4-3(x+2)-(6(x-2)-7)=0

We multiply parentheses

-3x-(6(x-2)-7)-6+4=0



We calculate terms in parentheses: -(6(x-2)-7), so:

6(x-2)-7

We multiply parentheses

6x-12-7

We add all the numbers together, and all the variables

6x-19

Back to the equation:

-(6x-19)



We add all the numbers together, and all the variables

-3x-(6x-19)-2=0

We get rid of parentheses

-3x-6x+19-2=0

We add all the numbers together, and all the variables

-9x+17=0

We move all terms containing x to the left, all other terms to the right

-9x=-17

x=-17/-9

x=1+8/9

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