4-3(x-1)=2(x+2)+8

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Solution for 4-3(x-1)=2(x+2)+8 equation:



4-3(x-1)=2(x+2)+8
We move all terms to the left:
4-3(x-1)-(2(x+2)+8)=0
We multiply parentheses
-3x-(2(x+2)+8)+3+4=0
We calculate terms in parentheses: -(2(x+2)+8), so:
2(x+2)+8
We multiply parentheses
2x+4+8
We add all the numbers together, and all the variables
2x+12
Back to the equation:
-(2x+12)
We add all the numbers together, and all the variables
-3x-(2x+12)+7=0
We get rid of parentheses
-3x-2x-12+7=0
We add all the numbers together, and all the variables
-5x-5=0
We move all terms containing x to the left, all other terms to the right
-5x=5
x=5/-5
x=-1

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