4-3/3k+7/6k-1/2=-k+2

Solution for 4-3/3k+7/6k-1/2=-k+2 equation:

4-3/3k+7/6k-1/2=-k+2

We move all terms to the left:

4-3/3k+7/6k-1/2-(-k+2)=0


Domain of the equation: 3k!=0

k!=0/3

k!=0

k∈R



Domain of the equation: 6k!=0

k!=0/6

k!=0

k∈R


We add all the numbers together, and all the variables

-3/3k+7/6k-(-1k+2)+4-1/2=0

We get rid of parentheses

-3/3k+7/6k+1k-2+4-1/2=0

We calculate fractions


(-108k^2)/72k^2+1k+(-72k)/72k^2+84k/72k^2-2+4=0

We add all the numbers together, and all the variables

(-108k^2)/72k^2+k+(-72k)/72k^2+84k/72k^2+2=0

We multiply all the terms by the denominator


(-108k^2)+k*72k^2+(-72k)+84k+2*72k^2=0

We add all the numbers together, and all the variables

(-108k^2)+84k+k*72k^2+(-72k)+2*72k^2=0

Wy multiply elements

(-108k^2)+72k^3+144k^2+84k+(-72k)=0

We get rid of parentheses

-108k^2+72k^3+144k^2+84k-72k=0

We do not support ekpression: k^3