4-4(6x+13)+12x=-8(2x+1)+12

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Solution for 4-4(6x+13)+12x=-8(2x+1)+12 equation: 



4-4(6x+13)+12x=-8(2x+1)+12

We move all terms to the left:

4-4(6x+13)+12x-(-8(2x+1)+12)=0

We add all the numbers together, and all the variables

12x-4(6x+13)-(-8(2x+1)+12)+4=0

We multiply parentheses

12x-24x-(-8(2x+1)+12)-52+4=0



We calculate terms in parentheses: -(-8(2x+1)+12), so:

-8(2x+1)+12

We multiply parentheses

-16x-8+12

We add all the numbers together, and all the variables

-16x+4

Back to the equation:

-(-16x+4)



We add all the numbers together, and all the variables

-12x-(-16x+4)-48=0

We get rid of parentheses

-12x+16x-4-48=0

We add all the numbers together, and all the variables

4x-52=0

We move all terms containing x to the left, all other terms to the right

4x=52

x=52/4

x=13

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