4-4(6x+13)+12x=2(1x-3)

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Solution for 4-4(6x+13)+12x=2(1x-3) equation: 



4-4(6x+13)+12x=2(1x-3)

We move all terms to the left:

4-4(6x+13)+12x-(2(1x-3))=0

We add all the numbers together, and all the variables

-4(6x+13)+12x-(2(x-3))+4=0

We add all the numbers together, and all the variables

12x-4(6x+13)-(2(x-3))+4=0

We multiply parentheses

12x-24x-(2(x-3))-52+4=0



We calculate terms in parentheses: -(2(x-3)), so:

2(x-3)

We multiply parentheses

2x-6

Back to the equation:

-(2x-6)



We add all the numbers together, and all the variables

-12x-(2x-6)-48=0

We get rid of parentheses

-12x-2x+6-48=0

We add all the numbers together, and all the variables

-14x-42=0

We move all terms containing x to the left, all other terms to the right

-14x=42

x=42/-14

x=-3

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