4-4(m-5)=2(2-m)-6

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Solution for 4-4(m-5)=2(2-m)-6 equation: 



4-4(m-5)=2(2-m)-6

We move all terms to the left:

4-4(m-5)-(2(2-m)-6)=0

We add all the numbers together, and all the variables

-4(m-5)-(2(-1m+2)-6)+4=0

We multiply parentheses

-4m-(2(-1m+2)-6)+20+4=0



We calculate terms in parentheses: -(2(-1m+2)-6), so:

2(-1m+2)-6

We multiply parentheses

-2m+4-6

We add all the numbers together, and all the variables

-2m-2

Back to the equation:

-(-2m-2)



We add all the numbers together, and all the variables

-4m-(-2m-2)+24=0

We get rid of parentheses

-4m+2m+2+24=0

We add all the numbers together, and all the variables

-2m+26=0

We move all terms containing m to the left, all other terms to the right

-2m=-26

m=-26/-2

m=+13

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