4-4(m-5)=2(2-m)-6

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Solution for 4-4(m-5)=2(2-m)-6 equation:



4-4(m-5)=2(2-m)-6
We move all terms to the left:
4-4(m-5)-(2(2-m)-6)=0
We add all the numbers together, and all the variables
-4(m-5)-(2(-1m+2)-6)+4=0
We multiply parentheses
-4m-(2(-1m+2)-6)+20+4=0
We calculate terms in parentheses: -(2(-1m+2)-6), so:
2(-1m+2)-6
We multiply parentheses
-2m+4-6
We add all the numbers together, and all the variables
-2m-2
Back to the equation:
-(-2m-2)
We add all the numbers together, and all the variables
-4m-(-2m-2)+24=0
We get rid of parentheses
-4m+2m+2+24=0
We add all the numbers together, and all the variables
-2m+26=0
We move all terms containing m to the left, all other terms to the right
-2m=-26
m=-26/-2
m=+13

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