If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4-4y-5y^2=0
a = -5; b = -4; c = +4;
Δ = b2-4ac
Δ = -42-4·(-5)·4
Δ = 96
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{96}=\sqrt{16*6}=\sqrt{16}*\sqrt{6}=4\sqrt{6}$$y_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-4)-4\sqrt{6}}{2*-5}=\frac{4-4\sqrt{6}}{-10} $$y_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-4)+4\sqrt{6}}{2*-5}=\frac{4+4\sqrt{6}}{-10} $
| 100-5=5x | | 6x+16=124 | | -27+4x=-4(x-5) | | 8a+96=−24 | | x-6=22+15x | | 4+7v=7v+8 | | 2/7*x=14 | | 2m-2=-18 | | 8y-3y=65 | | 9y+2y=121 | | -1+3n=7n+3-4n | | -5x+2x(x-30)=x | | 1/2(10-4x)=x/2 | | 6x+5=5x+3=9 | | 3n-9=2n-15 | | -9p=-54 | | 2x+1/x-3=4 | | -8-1x=-8 | | 5^(x+4)=18 | | -2(1+3y)=18 | | n-6=n-14 | | -2(1+3y=18 | | 75x-10=-12 | | 2|x|+3=17 | | 1+7n=7n+1 | | 8y−7=10y+6+5 | | -4=3p-13-2p | | 12x4=100 | | 8s+6=10+7s | | -42=-3y | | 2^{3x+2}=8 | | b-6=6-b |