4-5(.x-1)-40(3x+1)=12(X+1)

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Solution for 4-5(.x-1)-40(3x+1)=12(X+1) equation: 



4-5(.x-1)-40(3x+1)=12(x+1)

We move all terms to the left:

4-5(.x-1)-40(3x+1)-(12(x+1))=0

We add all the numbers together, and all the variables

-40(3x+1)-(12(x+1))+4-5(-1)=0

We add all the numbers together, and all the variables

-40(3x+1)-(12(x+1))+9=0

We multiply parentheses

-120x-(12(x+1))-40+9=0



We calculate terms in parentheses: -(12(x+1)), so:

12(x+1)

We multiply parentheses

12x+12

Back to the equation:

-(12x+12)



We add all the numbers together, and all the variables

-120x-(12x+12)-31=0

We get rid of parentheses

-120x-12x-12-31=0

We add all the numbers together, and all the variables

-132x-43=0

We move all terms containing x to the left, all other terms to the right

-132x=43

x=43/-132

x=-43/132

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