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4-5(2x-2)=2(x+1)
We move all terms to the left:
4-5(2x-2)-(2(x+1))=0
We multiply parentheses
-10x-(2(x+1))+10+4=0
We calculate terms in parentheses: -(2(x+1)), so:We add all the numbers together, and all the variables
2(x+1)
We multiply parentheses
2x+2
Back to the equation:
-(2x+2)
-10x-(2x+2)+14=0
We get rid of parentheses
-10x-2x-2+14=0
We add all the numbers together, and all the variables
-12x+12=0
We move all terms containing x to the left, all other terms to the right
-12x=-12
x=-12/-12
x=1
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