4-5(k+3)=-5(k-9)+7k

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Solution for 4-5(k+3)=-5(k-9)+7k equation:



4-5(k+3)=-5(k-9)+7k
We move all terms to the left:
4-5(k+3)-(-5(k-9)+7k)=0
We multiply parentheses
-5k-(-5(k-9)+7k)-15+4=0
We calculate terms in parentheses: -(-5(k-9)+7k), so:
-5(k-9)+7k
We add all the numbers together, and all the variables
7k-5(k-9)
We multiply parentheses
7k-5k+45
We add all the numbers together, and all the variables
2k+45
Back to the equation:
-(2k+45)
We add all the numbers together, and all the variables
-5k-(2k+45)-11=0
We get rid of parentheses
-5k-2k-45-11=0
We add all the numbers together, and all the variables
-7k-56=0
We move all terms containing k to the left, all other terms to the right
-7k=56
k=56/-7
k=-8

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