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4-5(y-1)=3(2y+1)
We move all terms to the left:
4-5(y-1)-(3(2y+1))=0
We multiply parentheses
-5y-(3(2y+1))+5+4=0
We calculate terms in parentheses: -(3(2y+1)), so:We add all the numbers together, and all the variables
3(2y+1)
We multiply parentheses
6y+3
Back to the equation:
-(6y+3)
-5y-(6y+3)+9=0
We get rid of parentheses
-5y-6y-3+9=0
We add all the numbers together, and all the variables
-11y+6=0
We move all terms containing y to the left, all other terms to the right
-11y=-6
y=-6/-11
y=6/11
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