4-6(1+3x)=-4(x+4)

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Solution for 4-6(1+3x)=-4(x+4) equation: 



4-6(1+3x)=-4(x+4)

We move all terms to the left:

4-6(1+3x)-(-4(x+4))=0

We add all the numbers together, and all the variables

-6(3x+1)-(-4(x+4))+4=0

We multiply parentheses

-18x-(-4(x+4))-6+4=0



We calculate terms in parentheses: -(-4(x+4)), so:

-4(x+4)

We multiply parentheses

-4x-16

Back to the equation:

-(-4x-16)



We add all the numbers together, and all the variables

-18x-(-4x-16)-2=0

We get rid of parentheses

-18x+4x+16-2=0

We add all the numbers together, and all the variables

-14x+14=0

We move all terms containing x to the left, all other terms to the right

-14x=-14

x=-14/-14

x=1

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