4-6(2x-2)=8(2x+4)+8

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Solution for 4-6(2x-2)=8(2x+4)+8 equation: 



4-6(2x-2)=8(2x+4)+8

We move all terms to the left:

4-6(2x-2)-(8(2x+4)+8)=0

We multiply parentheses

-12x-(8(2x+4)+8)+12+4=0



We calculate terms in parentheses: -(8(2x+4)+8), so:

8(2x+4)+8

We multiply parentheses

16x+32+8

We add all the numbers together, and all the variables

16x+40

Back to the equation:

-(16x+40)



We add all the numbers together, and all the variables

-12x-(16x+40)+16=0

We get rid of parentheses

-12x-16x-40+16=0

We add all the numbers together, and all the variables

-28x-24=0

We move all terms containing x to the left, all other terms to the right

-28x=24

x=24/-28

x=-6/7

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