4-6(8-x)=10(4-x)+8x

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Solution for 4-6(8-x)=10(4-x)+8x equation: 



4-6(8-x)=10(4-x)+8x

We move all terms to the left:

4-6(8-x)-(10(4-x)+8x)=0

We add all the numbers together, and all the variables

-6(-1x+8)-(10(-1x+4)+8x)+4=0

We multiply parentheses

6x-(10(-1x+4)+8x)-48+4=0



We calculate terms in parentheses: -(10(-1x+4)+8x), so:

10(-1x+4)+8x

We add all the numbers together, and all the variables

8x+10(-1x+4)

We multiply parentheses

8x-10x+40

We add all the numbers together, and all the variables

-2x+40

Back to the equation:

-(-2x+40)



We add all the numbers together, and all the variables

6x-(-2x+40)-44=0

We get rid of parentheses

6x+2x-40-44=0

We add all the numbers together, and all the variables

8x-84=0

We move all terms containing x to the left, all other terms to the right

8x=84

x=84/8

x=10+1/2

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