4-6(x+2)=2(x-5)+2=

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Solution for 4-6(x+2)=2(x-5)+2= equation: 



4-6(x+2)=2(x-5)+2=

We move all terms to the left:

4-6(x+2)-(2(x-5)+2)=0

We multiply parentheses

-6x-(2(x-5)+2)-12+4=0



We calculate terms in parentheses: -(2(x-5)+2), so:

2(x-5)+2

We multiply parentheses

2x-10+2

We add all the numbers together, and all the variables

2x-8

Back to the equation:

-(2x-8)



We add all the numbers together, and all the variables

-6x-(2x-8)-8=0

We get rid of parentheses

-6x-2x+8-8=0

We add all the numbers together, and all the variables

-8x=0

x=0/-8

x=0

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