4-6(x+4)=2(3x-1)+7x-4

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Solution for 4-6(x+4)=2(3x-1)+7x-4 equation: 



4-6(x+4)=2(3x-1)+7x-4

We move all terms to the left:

4-6(x+4)-(2(3x-1)+7x-4)=0

We multiply parentheses

-6x-(2(3x-1)+7x-4)-24+4=0



We calculate terms in parentheses: -(2(3x-1)+7x-4), so:

2(3x-1)+7x-4

We add all the numbers together, and all the variables

7x+2(3x-1)-4

We multiply parentheses

7x+6x-2-4

We add all the numbers together, and all the variables

13x-6

Back to the equation:

-(13x-6)



We add all the numbers together, and all the variables

-6x-(13x-6)-20=0

We get rid of parentheses

-6x-13x+6-20=0

We add all the numbers together, and all the variables

-19x-14=0

We move all terms containing x to the left, all other terms to the right

-19x=14

x=14/-19

x=-14/19

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