4-6(x-2)=3(x-1)+8

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Solution for 4-6(x-2)=3(x-1)+8 equation: 



4-6(x-2)=3(x-1)+8

We move all terms to the left:

4-6(x-2)-(3(x-1)+8)=0

We multiply parentheses

-6x-(3(x-1)+8)+12+4=0



We calculate terms in parentheses: -(3(x-1)+8), so:

3(x-1)+8

We multiply parentheses

3x-3+8

We add all the numbers together, and all the variables

3x+5

Back to the equation:

-(3x+5)



We add all the numbers together, and all the variables

-6x-(3x+5)+16=0

We get rid of parentheses

-6x-3x-5+16=0

We add all the numbers together, and all the variables

-9x+11=0

We move all terms containing x to the left, all other terms to the right

-9x=-11

x=-11/-9

x=1+2/9

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