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4-6(x-5)=2x+4(x-20)
We move all terms to the left:
4-6(x-5)-(2x+4(x-20))=0
We multiply parentheses
-6x-(2x+4(x-20))+30+4=0
We calculate terms in parentheses: -(2x+4(x-20)), so:We add all the numbers together, and all the variables
2x+4(x-20)
We multiply parentheses
2x+4x-80
We add all the numbers together, and all the variables
6x-80
Back to the equation:
-(6x-80)
-6x-(6x-80)+34=0
We get rid of parentheses
-6x-6x+80+34=0
We add all the numbers together, and all the variables
-12x+114=0
We move all terms containing x to the left, all other terms to the right
-12x=-114
x=-114/-12
x=9+1/2
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