4-7(2k+5)=4-7(2-5k)

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Solution for 4-7(2k+5)=4-7(2-5k) equation: 



4-7(2k+5)=4-7(2-5k)

We move all terms to the left:

4-7(2k+5)-(4-7(2-5k))=0

We add all the numbers together, and all the variables

-7(2k+5)-(4-7(-5k+2))+4=0

We multiply parentheses

-14k-(4-7(-5k+2))-35+4=0



We calculate terms in parentheses: -(4-7(-5k+2)), so:

4-7(-5k+2)

determiningTheFunctionDomain
-7(-5k+2)+4

We multiply parentheses

35k-14+4

We add all the numbers together, and all the variables

35k-10

Back to the equation:

-(35k-10)



We add all the numbers together, and all the variables

-14k-(35k-10)-31=0

We get rid of parentheses

-14k-35k+10-31=0

We add all the numbers together, and all the variables

-49k-21=0

We move all terms containing k to the left, all other terms to the right

-49k=21

k=21/-49

k=-3/7

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