4-7(3-2r)+7=5(r-2)-9

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Solution for 4-7(3-2r)+7=5(r-2)-9 equation: 



4-7(3-2r)+7=5(r-2)-9

We move all terms to the left:

4-7(3-2r)+7-(5(r-2)-9)=0

We add all the numbers together, and all the variables

-7(-2r+3)-(5(r-2)-9)+4+7=0

We add all the numbers together, and all the variables

-7(-2r+3)-(5(r-2)-9)+11=0

We multiply parentheses

14r-(5(r-2)-9)-21+11=0



We calculate terms in parentheses: -(5(r-2)-9), so:

5(r-2)-9

We multiply parentheses

5r-10-9

We add all the numbers together, and all the variables

5r-19

Back to the equation:

-(5r-19)



We add all the numbers together, and all the variables

14r-(5r-19)-10=0

We get rid of parentheses

14r-5r+19-10=0

We add all the numbers together, and all the variables

9r+9=0

We move all terms containing r to the left, all other terms to the right

9r=-9

r=-9/9

r=-1

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