4-7=1/4(y+2)

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Solution for 4-7=1/4(y+2) equation: 



4-7=1/4(y+2)

We move all terms to the left:

4-7-(1/4(y+2))=0



Domain of the equation: 4(y+2))!=0

y∈R



We add all the numbers together, and all the variables

-(1/4(y+2))-3=0

We multiply all the terms by the denominator


-(1-3*4(y+2))=0



We calculate terms in parentheses: -(1-3*4(y+2)), so:

1-3*4(y+2)

determiningTheFunctionDomain
-3*4(y+2)+1

Wy multiply elements

-12y(y+1

Back to the equation:

-(-12y(y+1)





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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-12y(y+1





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