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4-9x=3-10x(7-x)
We move all terms to the left:
4-9x-(3-10x(7-x))=0
We add all the numbers together, and all the variables
-9x-(3-10x(-1x+7))+4=0
We calculate terms in parentheses: -(3-10x(-1x+7)), so:We get rid of parentheses
3-10x(-1x+7)
determiningTheFunctionDomain -10x(-1x+7)+3
We multiply parentheses
10x^2-70x+3
Back to the equation:
-(10x^2-70x+3)
-10x^2-9x+70x-3+4=0
We add all the numbers together, and all the variables
-10x^2+61x+1=0
a = -10; b = 61; c = +1;
Δ = b2-4ac
Δ = 612-4·(-10)·1
Δ = 3761
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(61)-\sqrt{3761}}{2*-10}=\frac{-61-\sqrt{3761}}{-20} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(61)+\sqrt{3761}}{2*-10}=\frac{-61+\sqrt{3761}}{-20} $
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