4-g+2(3+g)=-4(g+1)

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Solution for 4-g+2(3+g)=-4(g+1) equation: 



4-g+2(3+g)=-4(g+1)

We move all terms to the left:

4-g+2(3+g)-(-4(g+1))=0

We add all the numbers together, and all the variables

-g+2(g+3)-(-4(g+1))+4=0

We add all the numbers together, and all the variables

-1g+2(g+3)-(-4(g+1))+4=0

We multiply parentheses

-1g+2g-(-4(g+1))+6+4=0



We calculate terms in parentheses: -(-4(g+1)), so:

-4(g+1)

We multiply parentheses

-4g-4

Back to the equation:

-(-4g-4)



We add all the numbers together, and all the variables

g-(-4g-4)+10=0

We get rid of parentheses

g+4g+4+10=0

We add all the numbers together, and all the variables

5g+14=0

We move all terms containing g to the left, all other terms to the right

5g=-14

g=-14/5

g=-2+4/5

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