4-t=3(t+-1)-5

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Solution for 4-t=3(t+-1)-5 equation: 



4-t=3(t+-1)-5

We move all terms to the left:

4-t-(3(t+-1)-5)=0

We add all the numbers together, and all the variables

-t-(3(t-1)-5)+4=0

We add all the numbers together, and all the variables

-1t-(3(t-1)-5)+4=0



We calculate terms in parentheses: -(3(t-1)-5), so:

3(t-1)-5

We multiply parentheses

3t-3-5

We add all the numbers together, and all the variables

3t-8

Back to the equation:

-(3t-8)



We get rid of parentheses

-1t-3t+8+4=0

We add all the numbers together, and all the variables

-4t+12=0

We move all terms containing t to the left, all other terms to the right

-4t=-12

t=-12/-4

t=+3

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