4-x-2(4-3x)=3(x-4)

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Solution for 4-x-2(4-3x)=3(x-4) equation: 



4-x-2(4-3x)=3(x-4)

We move all terms to the left:

4-x-2(4-3x)-(3(x-4))=0

We add all the numbers together, and all the variables

-x-2(-3x+4)-(3(x-4))+4=0

We add all the numbers together, and all the variables

-1x-2(-3x+4)-(3(x-4))+4=0

We multiply parentheses

-1x+6x-(3(x-4))-8+4=0



We calculate terms in parentheses: -(3(x-4)), so:

3(x-4)

We multiply parentheses

3x-12

Back to the equation:

-(3x-12)



We add all the numbers together, and all the variables

5x-(3x-12)-4=0

We get rid of parentheses

5x-3x+12-4=0

We add all the numbers together, and all the variables

2x+8=0

We move all terms containing x to the left, all other terms to the right

2x=-8

x=-8/2

x=-4

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