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4-x2/4=5x
We move all terms to the left:
4-x2/4-(5x)=0
We add all the numbers together, and all the variables
-5x-x2/4+4=0
We multiply all the terms by the denominator
-5x*4-x2+4*4=0
We add all the numbers together, and all the variables
-1x^2-5x*4+16=0
Wy multiply elements
-1x^2-20x+16=0
a = -1; b = -20; c = +16;
Δ = b2-4ac
Δ = -202-4·(-1)·16
Δ = 464
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{464}=\sqrt{16*29}=\sqrt{16}*\sqrt{29}=4\sqrt{29}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-20)-4\sqrt{29}}{2*-1}=\frac{20-4\sqrt{29}}{-2} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-20)+4\sqrt{29}}{2*-1}=\frac{20+4\sqrt{29}}{-2} $
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