4-y+2(4-y)+2y+y=12

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Solution for 4-y+2(4-y)+2y+y=12 equation: 



4-y+2(4-y)+2y+y=12

We move all terms to the left:

4-y+2(4-y)+2y+y-(12)=0

We add all the numbers together, and all the variables

-y+2(-1y+4)+2y+y+4-12=0

We add all the numbers together, and all the variables

2y+2(-1y+4)-8=0

We multiply parentheses

2y-2y+8-8=0

We add all the numbers together, and all the variables

=0

y=0/1

y=0

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