4-z/z+3/2=-4/z

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Solution for 4-z/z+3/2=-4/z equation: 


D( z )

z = 0

z = 0

z = 0

z in (-oo:0) U (0:+oo)

3/2-(z/z)+4 = -4/z // + -4/z

3/2-(-4/z)-(z/z)+4 = 0

4*z^-1+3/2-1+4 = 0

4*z^-1 = -9/2 // : 4

z^-1 = -9/8

-1 < 0

1/(z^1) = -9/8 // * z^1

1 = -9/8*z^1 // : -9/8

-8/9 = z^1

z = -8/9

z = -8/9

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