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4.17=r(2)
We move all terms to the left:
4.17-(r(2))=0
determiningTheFunctionDomain -r2+4.17=0
We add all the numbers together, and all the variables
-1r^2+4.17=0
a = -1; b = 0; c = +4.17;
Δ = b2-4ac
Δ = 02-4·(-1)·4.17
Δ = 16.68
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:r_{1}=\frac{-b-\sqrt{\Delta}}{2a}r_{2}=\frac{-b+\sqrt{\Delta}}{2a}r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-\sqrt{16.68}}{2*-1}=\frac{0-\sqrt{16.68}}{-2} =-\frac{\sqrt{}}{-2}r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+\sqrt{16.68}}{2*-1}=\frac{0+\sqrt{16.68}}{-2} =\frac{\sqrt{}}{-2}
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