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4.5+(3/5)x+10=2x+30
We move all terms to the left:
4.5+(3/5)x+10-(2x+30)=0
Domain of the equation: 5)x!=0We add all the numbers together, and all the variables
x!=0/1
x!=0
x∈R
(+3/5)x-(2x+30)+4.5+10=0
We add all the numbers together, and all the variables
(+3/5)x-(2x+30)+14.5=0
We multiply parentheses
3x^2-(2x+30)+14.5=0
We get rid of parentheses
3x^2-2x-30+14.5=0
We add all the numbers together, and all the variables
3x^2-2x-15.5=0
a = 3; b = -2; c = -15.5;
Δ = b2-4ac
Δ = -22-4·3·(-15.5)
Δ = 190
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-2)-\sqrt{190}}{2*3}=\frac{2-\sqrt{190}}{6} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-2)+\sqrt{190}}{2*3}=\frac{2+\sqrt{190}}{6} $
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