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1;3;2;5;3;0
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1*x^3+3*x^2-(16*x)+12 = 0
x^4+x^2+1;x^2+x+1
4*x^2-(16*x)+0*x^3+12 = 0
| x(11-2x)=10 | | 1r(r+12)=-7 | | 27-2x=-18+7x | | x(21-2x)=46 | | 6x+42=x+18 | | -3x-5x=-39-9 | | 7a+4c=40 | | x(21-2x)=21 | | 11r=10+10r | | -x-10=2x-5 | | 3(2x+1)-12=3 | | 2y+6x-5=0 | | X+3=-26+10 | | 816=(26+2x)(16+2x) | | x+1-5=5x+5 | | k+12=35 | | 1/3z=2 | | 8-3(x-2)= | | -w=5w^2-4 | | x=x/8-14 | | 40x+18x(x-3)=468 | | y/5=3/5 | | 6x^2-6x-36=-40 | | 5+1=2x+4 | | =(x+y)(x-y)+(2x-y)(3x+y) | | 27.6*9.6= | | 0=l^2+2-64 | | 10x+11y=95 | | -9x^2+4x+1=0 | | 0=l^2+2l-64 | | 0=w^2+10w-56 | | 0.6x^2+2x+1=0 |