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4.5r=3.2+4/5r
We move all terms to the left:
4.5r-(3.2+4/5r)=0
Domain of the equation: 5r)!=0We add all the numbers together, and all the variables
r!=0/1
r!=0
r∈R
4.5r-(4/5r+3.2)=0
We get rid of parentheses
4.5r-4/5r-3.2=0
We multiply all the terms by the denominator
(4.5r)*5r-(3.2)*5r-4=0
We add all the numbers together, and all the variables
(+4.5r)*5r-(3.2)*5r-4=0
We multiply parentheses
20r^2-16r-4=0
a = 20; b = -16; c = -4;
Δ = b2-4ac
Δ = -162-4·20·(-4)
Δ = 576
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{576}=24$$r_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-24}{2*20}=\frac{-8}{40} =-1/5 $$r_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+24}{2*20}=\frac{40}{40} =1 $
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