If it's not what You are looking for type in the equation solver your own equation and let us solve it.
4.9t^2-16t+7=0
a = 4.9; b = -16; c = +7;
Δ = b2-4ac
Δ = -162-4·4.9·7
Δ = 118.8
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-16)-\sqrt{118.8}}{2*4.9}=\frac{16-\sqrt{118.8}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-16)+\sqrt{118.8}}{2*4.9}=\frac{16+\sqrt{118.8}}{9.8} $
| 45x=456-678 | | -45=y/4 | | 4x+2=(3x+8) | | 49t2-16t+7=0 | | 2/5x+15=30 | | x^2=−100 | | -2(-5x-4)+x+1=19 | | (3x+50)=(6x-10) | | 3/2(x-5)=6/1 | | 4w+14=3w+84 | | 5+(x-3)=4 | | -6(5p+2)-48=4p+32 | | 2(8/4c)=32 | | 16z2+62=64z | | -r/4=-3π | | x^2−56=140 | | 32=5-(3t) | | -14=-3v | | 48828x-2848=4882938x+388928 | | 12x^2+6x=5 | | −12x^2=−1200 | | 6+(2x-10)=4 | | 4x^2+12=3x^+12 | | 4x+6-2x=2(x+3 | | 7(4x+2)=9(3x-7)+60 | | X2-21x+98=0 | | -x^2+10x-2=0 | | 3+b=-13-9 | | x^=0 | | -6w=23 | | 18x+9=5.7x-6 | | 2x+1+3x=1+4x-6 |