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4.9t^2-24t-15=0
a = 4.9; b = -24; c = -15;
Δ = b2-4ac
Δ = -242-4·4.9·(-15)
Δ = 870
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$t_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-24)-\sqrt{870}}{2*4.9}=\frac{24-\sqrt{870}}{9.8} $$t_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-24)+\sqrt{870}}{2*4.9}=\frac{24+\sqrt{870}}{9.8} $
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