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4.9x^2-6.93x+2.45=0
a = 4.9; b = -6.93; c = +2.45;
Δ = b2-4ac
Δ = -6.932-4·4.9·2.45
Δ = 0.00489999999999
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-6.93)-\sqrt{0.00489999999999}}{2*4.9}=\frac{6.93-\sqrt{0.00489999999999}}{9.8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-6.93)+\sqrt{0.00489999999999}}{2*4.9}=\frac{6.93+\sqrt{0.00489999999999}}{9.8} $
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