4/(2x+3)=5/(x+4)

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Solution for 4/(2x+3)=5/(x+4) equation: 



4/(2x+3)=5/(x+4)

We move all terms to the left:

4/(2x+3)-(5/(x+4))=0



Domain of the equation: (2x+3)!=0

We move all terms containing x to the left, all other terms to the right

2x!=-3

x!=-3/2

x!=-1+1/2

x∈R





Domain of the equation: (x+4))!=0

x∈R



We calculate fractions


4x/((2x+3)*(x+4)))+(-(5*(2x+3))/((2x+3)*(x+4)))=0



We calculate terms in parentheses: -(5*(2x+3))/((2x+3)*(x+4))), so:

5*(2x+3))/((2x+3)*(x+4))

We multiply all the terms by the denominator


5*(2x+3))

We multiply parentheses

10x+

We add all the numbers together, and all the variables

10x

Back to the equation:

-(10x)



We add all the numbers together, and all the variables

-10x+4x/((2x+3)*(x+4)))+(=0

We multiply all the terms by the denominator


-10x*((2x+3)*(x+4)))+(+4x=0

We add all the numbers together, and all the variables

4x-10x*((2x+3)*(x+4)))+(=0

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