4/(2x-1)=-3/(x+1)

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Solution for 4/(2x-1)=-3/(x+1) equation: 



4/(2x-1)=-3/(x+1)

We move all terms to the left:

4/(2x-1)-(-3/(x+1))=0



Domain of the equation: (2x-1)!=0

We move all terms containing x to the left, all other terms to the right

2x!=1

x!=1/2

x!=1/2

x∈R





Domain of the equation: (x+1))!=0

x∈R



We calculate fractions


4x/((2x-1)*(x+1)))+(-(-3*(2x-1))/((2x-1)*(x+1)))=0



We calculate terms in parentheses: -(-3*(2x-1))/((2x-1)*(x+1))), so:

-3*(2x-1))/((2x-1)*(x+1))

We multiply all the terms by the denominator


-3*(2x-1))

We multiply parentheses

-6x-

We add all the numbers together, and all the variables

-6x

Back to the equation:

-(-6x)



We get rid of parentheses

4x/((2x-1)*(x+1)))+(+6x=0

We multiply all the terms by the denominator


4x+6x*((2x-1)*(x+1)))+(=0

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