4/(3x)+3/4=13/(6x)+7/3

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Solution for 4/(3x)+3/4=13/(6x)+7/3 equation: 


D( x )

6*x = 0

3*x = 0

6*x = 0

6*x = 0

6*x = 0 // : 6

x = 0

3*x = 0

3*x = 0

3*x = 0 // : 3

x = 0

x in (-oo:0) U (0:+oo)

4/(3*x)+3/4 = 13/(6*x)+7/3 // - 13/(6*x)+7/3

4/(3*x)-(13/(6*x))+3/4-(7/3) = 0

4/(3*x)+(-13/6)*x^-1+3/4-7/3 = 0

-5/6*x^-1 = 19/12 // : -5/6

x^-1 = -19/10

-1 < 0

1/(x^1) = -19/10 // * x^1

1 = -19/10*x^1 // : -19/10

-10/19 = x^1

x = -10/19

x = -10/19

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