4/(3x-1)=2/(x+3)

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Solution for 4/(3x-1)=2/(x+3) equation: 



4/(3x-1)=2/(x+3)

We move all terms to the left:

4/(3x-1)-(2/(x+3))=0



Domain of the equation: (3x-1)!=0

We move all terms containing x to the left, all other terms to the right

3x!=1

x!=1/3

x!=1/3

x∈R





Domain of the equation: (x+3))!=0

x∈R



We calculate fractions


4x/((3x-1)*(x+3)))+(-(2*(3x-1))/((3x-1)*(x+3)))=0



We calculate terms in parentheses: -(2*(3x-1))/((3x-1)*(x+3))), so:

2*(3x-1))/((3x-1)*(x+3))

We multiply all the terms by the denominator


2*(3x-1))

We multiply parentheses

6x+

We add all the numbers together, and all the variables

6x

Back to the equation:

-(6x)



We add all the numbers together, and all the variables

-6x+4x/((3x-1)*(x+3)))+(=0

We multiply all the terms by the denominator


-6x*((3x-1)*(x+3)))+(+4x=0

We add all the numbers together, and all the variables

4x-6x*((3x-1)*(x+3)))+(=0

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