4/(3x-1)=6/(2x+1)

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Solution for 4/(3x-1)=6/(2x+1) equation:


D( x )

2*x+1 = 0

3*x-1 = 0

2*x+1 = 0

2*x+1 = 0

2*x+1 = 0 // - 1

2*x = -1 // : 2

x = -1/2

3*x-1 = 0

3*x-1 = 0

3*x-1 = 0 // + 1

3*x = 1 // : 3

x = 1/3

x in (-oo:-1/2) U (-1/2:1/3) U (1/3:+oo)

4/(3*x-1) = 6/(2*x+1) // - 6/(2*x+1)

4/(3*x-1)-(6/(2*x+1)) = 0

4/(3*x-1)-6*(2*x+1)^-1 = 0

4/(3*x-1)-6/(2*x+1) = 0

(4*(2*x+1))/((3*x-1)*(2*x+1))+(-6*(3*x-1))/((3*x-1)*(2*x+1)) = 0

4*(2*x+1)-6*(3*x-1) = 0

10-10*x = 0

(10-10*x)/((3*x-1)*(2*x+1)) = 0

(10-10*x)/((3*x-1)*(2*x+1)) = 0 // * (3*x-1)*(2*x+1)

10-10*x = 0

10-10*x = 0 // - 10

-10*x = -10 // : -10

x = -10/(-10)

x = 1

x = 1

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